The NFL has named Pittsburgh Steelers quarterback Ben Roethlisberger as the AFC Offensive Player of the Week for the second consecutive week.
Roethlisberger won the award at the Ravens' expense, throwing six touchdown passes and no interceptions during a 43-23 rout Sunday night at Heinz Field.
Roethlisberger completed 25 of 37 passes for 340 yards against the Ravens, who reacted to the secondary breakdowns by letting go of cornerbacks Dominique Franks and Chykie Brown on Tuesday. They replaced them by claiming Danny Gorrer off waivers from the Detroit Lions and promoting rookie Tramain Jacobs from the practice squad.
In the last two games, Roethlisberger has completed 65 of 86 passes (75.6 percent) for 862 yards, 12 touchdowns and no interceptions in wins over the Indianapolis Colts and Ravens, setting an NFL record for most touchdowns in two consecutive games.